w^2-4w-68=0

Solution for w^2-4w-68=0 equation:

w^2-4w-68=0

a = 1; b = -4; c = -68;
Δ = b2-4ac
Δ = -42-4·1·(-68)
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-12\sqrt{2}}{2*1}=\frac{4-12\sqrt{2}}{2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+12\sqrt{2}}{2*1}=\frac{4+12\sqrt{2}}{2}
$